7x/x^2-x-2+x/x^2+4x+3

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Solution for 7x/x^2-x-2+x/x^2+4x+3 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x-x+(7*x)/(x^2)+x/(x^2)-2+3 = 0

3*x^1+8*x^-1+1*x^0 = 0

(3*x^2+1*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2+1*x^1+8*x^0) = 0

x^1

3*x^2+x+8 = 0

3*x^2+x+8 = 0

DELTA = 1^2-(3*4*8)

DELTA = -95

DELTA < 0

x in { } 

x belongs to the empty set

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